Nuclei | NCERT Solutions XII | 13.1 to 13.10 | Rationalized content
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Q13.1 00:00:00 Q13.2 00:05:33 Q13.3 00:14:43
Q13.4 00:22:41 Q13.5 00:24:21 Q13.6 00:32:18
Q13.7 00:38:11 Q13.8 00:42:12 Q13.9 00:47:44
Q13.10 00:55:03

13.1 Obtain the binding energy (in MeV) of a nitrogen nucleus (14)(7)N, given m(14)(7)N =14.00307 u
13.2 Obtain the binding energy of the nuclei (56)(26)Fe and (209)(83) Bi in units of MeV from the following data:
m (56)(26Fe ) = 55.934939 u
m (209)(83 Bi ) = 208.980388 u
13.3 A given coin has a mass of 3.0 g. Calculate the nuclear energy that
would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of (63)(29)Cu atoms (of mass 62.92960 u).
13.4 Obtain approximately the ratio of the nuclear radii of the gold isotope
(197)(79) Au and the silver isotope (107)(47) Ag .
13.5 The Q value of a nuclear reaction A + b gives C + d is defined by
Q = [ mA + mb – mC – md]c2
where the masses refer to the respective nuclei. Determine from the
given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic.
13.6 Suppose, we think of fission of a (56)(26) Fe nucleus into two equal
fragments, (28) (13) Al . Is the fission energetically possible? Argue by
working out Q of the process. Given m (56) (26) Fe = 55.93494 u and
m (28)(13) Al = 27.98191 u.
13.7 The fission properties of (239)(94) Pu are very similar to those of
(235)(92) U . The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure (239)
(94) Pu undergo fission?
13.8 How long can an electric lamp of 100W be kept glowing by fusion of
2.0 kg of deuterium? Take the fusion reaction as
13.9 Calculate the height of the potential barrier for a head on collision
of two deuterons. (Hint: The height of the potential barrier is given
by the Coulomb repulsion between the two deuterons when they
just touch each other. Assume that they can be taken as hard
spheres of radius 2.0 fm.)
13.10 From the relation R = R0A1/3, where R0 is a constant and A is the
mass number of a nucleus, show that the nuclear matter density is
nearly constant (i.e. independent of A).

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